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Remove absolute HP from the capture chance formula.

This commit is contained in:
Eevee 2010-03-27 19:47:36 -07:00
parent c309f52d6a
commit d995942b4f
1 changed files with 12 additions and 5 deletions
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17
pokedex/formulae.py
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@ -44,9 +44,10 @@ def earned_exp(base_exp, level):
return base_exp * level // 7
def capture_chance(current_hp, max_hp, capture_rate,
def capture_chance(percent_hp, capture_rate,
ball_bonus=1, status_bonus=1, heavy_modifier=0):
"""Calculates the chance that a Pokémon will be caught.
"""Calculates the chance that a Pokémon will be caught, given its capture
rate and the percentage of HP it has remaining.
Returns five values: the chance of a capture, then the chance of the ball
shaking three, two, one, or zero times. Each of these is a float such that
@ -63,9 +64,15 @@ def capture_chance(current_hp, max_hp, capture_rate,
# ROOTS in a moment, so it can't possibly be. It probably doesn't matter
# either way, so whatever; use regular ol' division. ball_bonus and
# status_bonus can be 1.5, anyway.
base_chance = ((3 * max_hp - 2 * current_hp) * capture_rate * ball_bonus) \
/ (3 * max_hp) \
* status_bonus
# A slight math note:
# The formula is originally: (3 max - 2 curr) rate bonus / (3 max)
# I have reduced this to: (1 - 2/3 * pct) rate bonus
# My rationale is that this cannot possibly be integer math, so rounding is
# not a problem and commutation won't make a difference. It also
# simplifies the input considerably.
base_chance = (1 - 2/3 * percent_hp) * capture_rate \
* ball_bonus * status_bonus
shake_index = (base_chance / 255) ** 0.25 * (2**16 - 1)